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contest_2011-09-13 [2011/09/11 08:18] jtkorbcontest_2011-09-13 [2011/09/20 14:34] (current) – old revision restored jtkorb
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   * A: [[http://uva.onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=33&page=show_problem&problem=1143|Pairsumonious Numbers]]   * A: [[http://uva.onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=33&page=show_problem&problem=1143|Pairsumonious Numbers]]
 +  * B: [[http://uva.onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=32&page=show_problem&problem=1132|Longest Nap]]
 +  * C: [[http://uva.onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=32&page=show_problem&problem=967|Shoemaker's Problem]]
 +  * D: [[http://uva.onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=34&page=show_problem&problem=1154|How Many Pieces of Land?]]
 +  * E: [[http://uva.onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=34&page=show_problem&problem=990|Self-describing Sequence]]
  
-If you've already solved one or more of these problems, try (1) solving again without referring to your old solution, and/or (2) using a different language (Java or C++).  If you want to work on an additional problem from this chapter, let [[jtk@purdue.edu|me]] know.+//Remember:// If you've already solved one or more of these problems, try (1) solving again without referring to your old solution, and/or (2) using a different language (Java or C++).  If you want to work on an additional problem from the book, let [[jtk@purdue.edu|me]] know.
  
 **Hints:** **Hints:**
  
   * A: Solve [[prelude_to_pairsumonious_numbers|Prelude to Pairsumonious Numbers]] first.  An exhaustive search of all possible sums works.  Create a candidate vector by seeding the first location with 1/2 of the first (lowest) sum.  Extend the vector by subtracting the current vector element from one of the sums.  Each time the vector fills, check to see if it is a solution.  If not, backtrack by selecting a different sum value at each of the extension steps.  Tricky bits: watch for sums less than 0 and only extend the current candidate solution vector if the entries are non-decreasing.  The check solution procedure verifies that the pair-wise sum of every pair of values has been found.   * A: Solve [[prelude_to_pairsumonious_numbers|Prelude to Pairsumonious Numbers]] first.  An exhaustive search of all possible sums works.  Create a candidate vector by seeding the first location with 1/2 of the first (lowest) sum.  Extend the vector by subtracting the current vector element from one of the sums.  Each time the vector fills, check to see if it is a solution.  If not, backtrack by selecting a different sum value at each of the extension steps.  Tricky bits: watch for sums less than 0 and only extend the current candidate solution vector if the entries are non-decreasing.  The check solution procedure verifies that the pair-wise sum of every pair of values has been found.
 +  * B: This problem is from the chapter on sorting.  Comparators help here.
 +  * C: See B.
 +  * D: Once you see the trick, the solution is easy with big integers (are they required?).
 +  * E: Pre-compute a run-length encoded array to represent f, then do a binary search to find f(n).
contest_2011-09-13.txt · Last modified: 2011/09/20 14:34 by jtkorb